.
Let P be the rate of the pipe (in the unit "tank volume per hour").
Let L be the rate of the leak (in the same unit).
Then you have two equations:
P - L = (1) (The pipe fills the tank in 10 hours, when the leak is in action).
P = . (2) ("The pipe can fill a water tank in 8 hours.")
Substitute (2) into equation (1). You will get
- L = ---> L = = = .
So, due to the leak, amount of water of of the tank volume goes out.
It means, that the full tank will become empty in 40 hours due to the leak.
Solved.
It is a typical joint work problem.
For a wide variety of similar solved joint-work problems with detailed explanations see the lessons
- Using Fractions to solve word problems on joint work
- Solving more complicated word problems on joint work
- Selected joint-work word problems from the archive
in this site.
Read them and get be trained in solving joint-work problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the topic "Rate of work and joint work problems" of the section "Word problems".