SOLUTION: find the equation of the tangent line for y=x^3-3x+1 at point (2,3)

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Question 1070565: find the equation of the tangent line for
y=x^3-3x+1
at point (2,3)

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
The derivative of x^3-3x+1=3x^2-3
When x=2, the slope is 9.
point slope formula at (2,3) with slope 9 is y-y1=m(x-x1), m the slope and (x1,y1) the point
y-3=9*(x-2)
y=9x-15


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