SOLUTION: Two cyclists leave a city at the same​ time, one going east and the other going west. The west bound cyclist bikes at 18 mph faster than the east bound cyclist. After 5 hours
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Question 1070458: Two cyclists leave a city at the same time, one going east and the other going west. The west bound cyclist bikes at 18 mph faster than the east bound cyclist. After 5 hours they are 180 miles apart. How fast is each cyclist riding?
Found 2 solutions by addingup, josgarithmetic:
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
5x+5x+18 = 180
10x = 162
x = 16.2 this is the speed of the slower cyclist
x+18 = 16.2+18 = 34.2 is the speed of the faster cyclist
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Eastbound cyclist:
Westbound cyclist:
Distance between the cyclists is given as 180 miles:
.
-
-----speed of the eastbound cyclist
------speed of the westbound cyclist
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