SOLUTION: Airplane 1 leaves city A for city B at the same time Airplane 2 leaves city B for city A. The distance from city A to city B is 565 miles. If Airplane 1 travels at 560 miles per ho

Question 1070251: Airplane 1 leaves city A for city B at the same time Airplane 2 leaves city B for city A. The distance from city A to city B is 565 miles. If Airplane 1 travels at 560 miles per hour and Airplane 2 travels at 570 miles per hour, how long into their flights will the two planes pass each other?
Thank you!
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
.
Airplane 1 leaves city A for city B at the same time Airplane 2 leaves city B for city A. The distance from city A to city B is 565 miles.
If Airplane 1 travels at 560 miles per hour and Airplane 2 travels at 570 miles per hour, how long into their flights
will the two planes pass each other?
Thank you!
~~~~~~~~~~~~~~~~~~~~~~

t =  =  = 0.5 of an hour = 30 minutes.   (*)


The numerator 565 is the distance, in miles;

the denominator 560 + 570 = 1130 is the relative speed of the two planes, or the rate of decreasing the distance between them.


The formula (*) which I used is the standard formula  t = .

On such problems, see the introductory lesson
- Travel and Distance problems
in this site.

There is a bunch of lessons on Travel and Distance in this site.

See the online textbook
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
under the topic "Travel and distance".

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