18180 = (2132)180 = 21803360 Let N be the least integer power of 12 that is divisible by 18180. 12N = (2231)N = 22N3N So we divide:= 2(2N-180)3(N-360). The smallest integers N can be must be just enough to make sure those powers of 2 and 3 are not negative. So N-360 = 0 or N = 360, (and certainly then 2N-180 = 360-180=180 is not negative.) So N = 360. Edwin