SOLUTION: can you please solve the following problem?
The population of a town increased by 50/3%
in 1990 and by 10% in 1991. If the population of the town at the beginning of 1990 was
Algebra.Com
Question 1061150: can you please solve the following problem?
The population of a town increased by 50/3%
in 1990 and by 10% in 1991. If the population of the town at the beginning of 1990 was 30,000, what was it at the end of 1991?
-Thank you.
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let n be your initial population. Then the town increased by 50/3% the first year, so it is 1+50/3% times its original size, or 3000 x 1.166666667, or 3500. Similarly, the next year it was 3500 x 1.1, or 3850, by the end of 1991. ☺☺☺☺
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