SOLUTION: solve the equation sin(y+π/6)cos(y+π/6)= cos^2(y+π/6), for 0≤y≤6, giving your answers in terms of π.

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Question 1056163: solve the equation sin(y+π/6)cos(y+π/6)= cos^2(y+π/6), for 0≤y≤6, giving your answers in terms of π.
Found 2 solutions by algebra hello, ikleyn:
Answer by algebra hello(55)   (Show Source): You can put this solution on YOUR website!
sin(y+π/6)cos(y+π/6)= cos^2(y+π/6)
sin(y+π/6)cos(y+π/6)/cos^2(y+π/6)=1
sin(y+π/6)/cos(y+π/6)=1
tan(y+π/6)=1
tan(y+π/6)=tanπ/4
(y+π/6)=π/4
y=π/4-π/6
y=π/12
Answer by ikleyn(52797)   (Show Source): You can put this solution on YOUR website!
.
sin(y+π/6)cos(y+π/6)= cos^2(y+π/6)

sin(y+π/6)cos(y+π/6)/cos^2(y+π/6)=1

sin(y+π/6)/cos(y+π/6)=1

tan(y+π/6)=1

tan(y+π/6)=tan(π/4)

(y+π/6) = ,    (since tan is periodical with the period )

y = π/4-π/6,   y =    (two solutions)

y = ,  y =    (two solutions)


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