SOLUTION: Marge left her home in Springfield at 9:00 A.M. and drove to Shelbyville, arriving at 10:45 A.M. She went shopping at the Shelbyville Galleria and had lunch at Krusty Burger in th

Question 1054600: Marge left her home in Springfield at 9:00 A.M. and drove to Shelbyville, arriving at 10:45 A.M.
She went shopping at the Shelbyville Galleria and had lunch at Krusty Burger in the food court. She
left to return home at 2:15 P.M. Because it had started raining, she drove 10 mph slower than she
did that morning. Marge got home at 4:15 P.M. What is the distance between the two cities?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Her driving time to Shelbyville was
10:45 minus 9:00 = hrs
( I converted 45 min to hrs )
----------------------------------
Her driving time back to Springfield was
4:15 minus 2:15 = hrs
----------------------------------
Let = her speed in mi/hr
driving to Shelbyville
= her speed driving back
to Springfield in mi/hr
----------------------------------
Let = the distance between
the two cities in miles
----------------------------------
Equation for drive to Shelbyville:
(1)
Equation for drive back to Springfield:
(2)
----------------------------------
Substitute (1) into (2)
(2)
(2)
(2)
(2)
--------------------
(1)
(1)
(1)
the distance between the 2 cities is 140 mi
--------------------
check answer:
(2)
(2)
(2)
(2)
OK
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