SOLUTION: A large shipment of watermelons has weights that are normally distributed with a standard deviation of 0.71 kg. The probability that a watermelon weights less than 2.1 kg is 10.2%.

Question 1042166: A large shipment of watermelons has weights that are normally distributed with a standard deviation of 0.71 kg. The probability that a watermelon weights less than 2.1 kg is 10.2%. The mean shipment to the nearest hundredth of a kg is
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!

A large shipment of watermelons has weights that are normally distributed with a standard deviation of 0.71 kg. The probability that a watermelon weights less than 2.1 kg is 10.2%. The mean shipment to the nearest hundredth of a kg is ?
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Find the z-value with a left tail of 10.2%
invNorm(0.102) = -1.2703
Using x = z*s + u,
2.1 = -1.2703*0.71 + u
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u = 3.00
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Cheers,
Stan H.
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