SOLUTION: g(x)=3x^2-4x+27 g(1-t)

Question 1036456: g(x)=3x^2-4x+27
g(1-t)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
g(x)=3x^2-4x+27
g(1-t) = 3(1-t)^2 - 4(1-t) + 27
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g(1-t) = 3(1-2t+t^2) - 4(1-t) + 27
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g(1-t) = 3 - 6t + 3t^2 - 4 + 4t + 27
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g(1-t) = 3t^2 - 2t + 26
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Cheers,
Stan H.
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