SOLUTION: given f(x) = (x^3 + 3x + 2)/(x^2-1), find f'(x)

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Question 1034456: given f(x) = (x^3 + 3x + 2)/(x^2-1), find f'(x)
Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
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given f(x) = (x^3 + 3x + 2)/(x^2-1), find f'(x)
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Use the derivative rule for the quotient: 


if  f(x) = ,  then  f'(x) = (u'*v - u*v')/v^2.   (1)


In your case  u =   and  v = ,  so

u' =   and  v' = .


Substitute it into (1) and simplify.


You are CALCULUS !

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