SOLUTION: g(t) = (t^2 + 2)/ (2t-7), find g'(t)

Question 1034455: g(t) = (t^2 + 2)/ (2t-7), find g'(t)
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
the denominator is (2t-7)^2
the numerator is (2t-7)(t^2)-(t^2+2)(2). That is 2t^3-7t^2-2t^2-4
{2t^3-9t^2-4)}/(2t-7)^2
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This can be done with the product rule, but it may be more difficult
write as (t^2+2)(2t=7)^(-1)
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