SOLUTION: a and b are positive integers. Find 2a+3b if a^2b^3=108
Algebra.Com
Question 1028080: a and b are positive integers. Find 2a+3b if a^2b^3=108
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Given a^2b^3=108, the only way this can be is if a = 2 and b = 3...because
2^2 * 3^3 = 4 * 27 = 108...if so, then
2a + 3b = 2*2 + 3*3 = 13
RELATED QUESTIONS
a and b are positive integers. Find −2a+3b if... (answered by robertb)
(a)/(2a+2b)-(b)/(3a+3b) (answered by MathLover1)
Given three positive integers a, b, and c, that satisfy both 2a + 3b + 4c = 25 and
4a +... (answered by jsmallt9)
If a,b, and c are positive integers, find the sum a + b + c if:
{{{a^3b^3c =... (answered by greenestamps)
If a,b and c are positive integers, find the sum a+b+c if:
{{{a^3b^2c = 3528, ab^3c^2 =... (answered by greenestamps)
3b+2a=2 and... (answered by jim_thompson5910)
8/2a-2b - 3b/a^2-b^2
HELP... (answered by tutorcecilia)
Evaluate the following expressions if a = -2 and b = 4.... (answered by checkley71)
How many ordered pairs of positive integers (a,b) satisfy the following equation? 2a + 3b (answered by LinnW)