SOLUTION: My question is: Jo has 37 coins (all nickels, dimes, and quarters) worth $5.50. She has 4 more quarters than nickels. How many dimes does Jo have? I am supposed to figure out

Question 102709This question is from textbook Algebra
: My question is:
Jo has 37 coins (all nickels, dimes, and quarters) worth $5.50. She has 4 more quarters than nickels. How many dimes does Jo have?
I am supposed to figure out how many dimes she has and I have to figure out my equations with a chart to help me. So far I have concluded that:
1.) Number of Coins x Value of coins = Total value ($5.50) is the equation
2.) Nickels-- .05N
3.) Dimes-- (37-N).10
4.) Quarters-- (4+N).25
This question is from textbook Algebra

Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
your expressions look OK except for the dimes ... you subtracted the nickels from the total but not the quarters

try Dimes-- (37-N-(N+4)).10

the three expressions summed together equal the total value
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