SOLUTION: A rectangle has a perimeter of 46 inches. The width of the rectangle is 7 inches shorter than twice its length. if a squares side is as long as the width of this rectangle, find th

Algebra.Com
Question 1015583: A rectangle has a perimeter of 46 inches. The width of the rectangle is 7 inches shorter than twice its length. if a squares side is as long as the width of this rectangle, find the perimeter of the square.
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
w and L width and length;
w=-7+2L, and 2w+2L=46.



and continue....

RELATED QUESTIONS

Stuck on this problem, it would be appreciated if steps were shown. thanks! A... (answered by mananth)
The length of a rectangle is five inches less than twice its width. If the rectangle has... (answered by Alan3354)
The length of a rectangle is 8 inches more than twice its width. If the perimeter of the (answered by Paul)
The length of a rectangle is 8 inches more than twice its width. If the perimeter of the (answered by fractalier,Earlsdon)
The length of a rectangle is 7 inches shorter than twice its width. If the width is... (answered by MathLover1)
The width of a rectangle is 4 inches less than one half the length. Find the length and... (answered by Stitch)
The width of a rectangle is 7 inches shorter than its length. The are is 78 square... (answered by mathizhard)
The length of a rectangle is 7 inches longer than it is wide. If the perimeter is 30... (answered by josgarithmetic)
The length of a rectangle is 7 inches greater than its width. The perimeter of the... (answered by josgarithmetic)