SOLUTION: 5x^2-25x+20=0
Algebra.Com
Question 1015278: 5x^2-25x+20=0
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
5x^2 -25x +20 = 0
divide both sides of = by 5
x^2 -5x +4 = 0
fator polynomial
(x-4) * (x-1) = 0
Note that * means multiply
then
x-4 = 0
x = 4
:
x-1 = 0
x = 1
:
solution is x = 4 or 1
:
verify our solution by substituting for x in original equation
5*(1^2) -(25*(1)) +20 = 0
5 -25 +20 = 0
0 = 0
:
5*(4^2) -(25*(4)) +20 = 0
80 -100 +20 = 0
0 = 0
:
our answer checks
RELATED QUESTIONS
how to factor quadratic equation: 5X^2 + 25X + 5=... (answered by jim_thompson5910)
(5x^4)(25x^2)^-1 (answered by stanbon)
25x^2-36/5x+6 (answered by Boreal)
simplify... (answered by jim_thompson5910)
show that 25x^2-25x+4=0
(answered by richwmiller)
25x^2+25=0 (answered by dabanfield)
X^2-25x=0 (answered by checkley79)
I need help factoring out this problem{{{20x^3+16x^2+25x+20=0}}}
I did it in two group... (answered by jim_thompson5910,Alan3354)
multiply
(-5x^2+4y)(5x^2+5y+z)
a. -25x^4-5x^2y^2+20y^2
b. -25x^2-5xy-5x^2z+20y^2+4z... (answered by jim_thompson5910)