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A takes 10 more days to do a job than B. They both do a job in 12 days.
In how many days B will take to complete the work if he works alone??
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Let a = # of days for A to do the job working alone, and
Let b = # of days for B to do the job working alone.
According to the condition, you have this system of two equations in two unknowns a and b:
a = b + 10, (1)
. = 1. (2)
From (1), substitute a = b + 10 into (2). You will get
. = . (3)
In (3), multiply both sides by b*(b+10) to get off the denominators. You will get
12*b + 12*(b+10) = b*(b+10), or
24b + 120 = , or
= , or
= .
Factor left side:
(b-20)*(b+6) = 0.
The roots are b = 20 and b = -6.
Only positive b = 20 fits the condition.
Then a = b + 10 = 30.
Answer. It will take 20 days for B to complete the job working alone.
For more details and more solved similar problems on joint work see the lessons
- Using fractions to solve word problems on joint work and
- Solving more complicated word problems on joint work
in this site.