SOLUTION: In the expression (mx^3-2x)(2x^2+3x-4)-(2x^5+4x^4) how can I fing the value of m? This is simplified to 4x^5+5x^4+8x^3-16x^3-6x^2+8

Question 1012583: In the expression (mx^3-2x)(2x^2+3x-4)-(2x^5+4x^4) how can I fing the value of m?
This is simplified to 4x^5+5x^4+8x^3-16x^3-6x^2+8
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
In the expression (mx^3-2x)(2x^2+3x-4)-(2x^5+4x^4) how can I fing the value of m?
This is simplified to 4x^5+5x^4+8x^3-16x^3-6x^2+8
=================
If you mean (mx^3-2x)(2x^2+3x-4)-(2x^5+4x^4) = 4x^5+5x^4+8x^3-16x^3-6x^2+8,
then the product or mx^3*2x^2 has to be 6x^5 since subtracting 2x^5 gives 4x^5.
--> m = 3

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