SOLUTION: Two buses left town A for town B at the same time. The speed of one of the buses was 10 mph greater than the speed of the other bus. In 3 .5 hours one bus reached town B, while th

Question 1011027: Two buses left town A for town B at the same time. The speed of one of the buses was 10 mph greater than the speed of the other bus. In 3 .5 hours one bus reached town B, while the other bus was away from town B at a distance equal 1/ 6 of the distance between A and B. Find the speed of the buses and the distance between A and B.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
I'll give it a shot, but it's a
little hard to follow
-----------------------
Let = the speed of the slower bus in mi/hr
= the speed of the faster bus in mi/hr
Let = the distance between the towns in miles
--------------------------------------------
Equation for the faster bus:
(1)
Equation for the slower bus:
(2)
-------------------------
(1)
and
(2)
-------------------

----------------
(2)
(2)
(2)
----------------
The speed of the slower bus was 2 mi/hr
The speed of the faster bus was 12 mi/hr
The distance between A and B was 42 mi
-----------------
check:
(1)
(1)
(1)
OK
---------
These numbers are a little strange -check my math
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