SOLUTION: h(t)=-16t^2+64t+720

Question 1000950: h(t)=-16t^2+64t+720
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
h(t)=-16t^2+64t+720
not sure what is wanted, but will get vertex and zeros. These are usually projectile problams. Something is 720 feet off the ground and thrown upwards at 64 feet/second
0=-16t^2+64t+720
0=-t^2+4t+45
0=t^2-4t-45
(t-9)(t+5)=0
t=9, -5
usually want the positive number. Hits the ground (0) at 9 seconds.
The vertex t or highest point is -b/2a=-64/-32=2 seconds.
h(2)=-64+128+720=784 feet.

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