SOLUTION: 2/5m=3 4/5=m=6 what was done to the first equation to get the second one? 2x=10 2x+4=14 what was done to the first equation to get the second one?

Algebra ->  Expressions-with-variables -> SOLUTION: 2/5m=3 4/5=m=6 what was done to the first equation to get the second one? 2x=10 2x+4=14 what was done to the first equation to get the second one?      Log On


   

Question 97361This question is from textbook Algebra 1
: 2/5m=3
4/5=m=6
what was done to the first equation to get the second one?
2x=10
2x+4=14
what was done to the first equation to get the second one? This question is from textbook Algebra 1

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%282%2F5%29m=3

===> multiply both sides by 2 to get 2%2A%282%2F5%29m=2%2A3==>%284%2F5%29m=6



2x=10

===> Add 4 to both sides to get 2x%2B4=10%2B4==>2x%2B4=14