SOLUTION: How do I solve this with substitution?
-x+y+z=3
-3x+2y+5z=13
3x-2y-5z=-13
Algebra.Com
Question 947284: How do I solve this with substitution?
-x+y+z=3
-3x+2y+5z=13
3x-2y-5z=-13
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do I solve this with substitution?
-x+y+z=3
-3x+2y+5z=13
3x-2y-5z=-13
----------
Why would you want to??
Cheers,
Stan H.
--------------
RELATED QUESTIONS
how do solve... (answered by Alan3354)
solve the system x-y-5z+-13
4x+2y+2z=6... (answered by Alan3354)
solve the system x-y-5z=-13
4x+2y+2z=6... (answered by Fombitz)
2x+y-5z+11=0
3x+y+2z-13=0... (answered by Alan3354)
How to do the System of equations. It says solve the system of equations
a)... (answered by MathLover1)
4x+2y+z=-1
3x-4y+5z=-13... (answered by Fombitz)
4x+2y+z=-1
3x-4y+5z=-13... (answered by Fombitz)
Write the augmented matrix for each of the following systems. Do not solve.
a)... (answered by MathLover1)
x+2y+3z=11
2x-y+4z=13... (answered by richwmiller)