SOLUTION: Let x=1 and y=2. Find the value of the given letter.
N=x^2+2xy+y^2+1
N=
Algebra.Com
Question 940101: Let x=1 and y=2. Find the value of the given letter.
N=x^2+2xy+y^2+1
N=
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Duplicate question.
See Answer 572911
RELATED QUESTIONS
Let x=1 and y=2. Find the value of the given capital letter.
N=x^2+2xy+y^2+1
N=... (answered by Fombitz,krutarthas,Shin123)
N=x^2+2xy+y^2+1 n=
(answered by checkley79)
Solve equation for y then find value of for the given value of x
2xy +1 = xy +3; x... (answered by jim_thompson5910)
Let x and y be real numbers. Find the maximum value of (x + y)^2, if x and y satisfy x^2 (answered by CPhill,ikleyn,Edwin McCravy)
Let X and Y be independent random variables with distributions... (answered by textot)
1. Let X(k) denote the N-point DFT of the N-point sequence x(n)
a) If x(n)... (answered by Fombitz)
If x > 0 and y> 0 and x^2 - y^2 = 2xy, find the exact value of... (answered by ikleyn)
What is the value of the polynomial x^2 - 2xy + 3y^2 when x= -1 and y =... (answered by ikleyn)
Ix x>0, y>0 and {{{x^2 -y^2 =2xy}}}, find the exact value of {{{x/y}}}.... (answered by josgarithmetic,ikleyn)