SOLUTION: If x + 2y + 3z = 6, 2x + 3y + z = 8 and 3x + y + 2z = 10, what is the value of x + y + z?
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Question 937871: If x + 2y + 3z = 6, 2x + 3y + z = 8 and 3x + y + 2z = 10, what is the value of x + y + z?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x + 2y + 3z = 6
2x + 3y + z = 8
3x + y + 2z = 10
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put the system of linear equations into standard form
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x + 2y + 3z = 6
2x + 3y + z = 8
3x + y + 2z = 10
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solution by matrix method:
x = 2.666666
y = 0.666666
z = 0.666666
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now by elimination:
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(x + 2y + 3z = 6)*(-2)
2x + 3y + z = 8
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-2x - 4y - 6z = -12
2x + 3y + z = 8
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add the two above:
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-y - 5z = -4
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(x + 2y + 3z = 6)*(-3)
3x + y + 2z = 10
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-3x - 6y - 9z = -18
3x + y + 2z = 10
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add the two above:
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-5y - 7z = -8
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-5y - 7z = -8
(-y - 5z = -4)*(-5)
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-5y - 7z = -8
5y + 25z = 20
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add the two above:
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18z = 12
z = 12/18
z = 0.666666
-y - 5z = -4
y = 4 - 5z
y = 0.666666
x + 2y + 3z = 6
x = 6 - (2y + 3z)
x = 2.666666
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solution by elimination:
x = 2.666666
y = 0.666666
z = 0.666666
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