SOLUTION: I have a few more problems. Can you please show me how to solve these problems such as:
7(6-(-8)) = t/-4 +2,
4x+5 = 3x-3,
6y=5 = 4y-13,and
7p-8 = -4p+6.
Thank you.
Algebra.Com
Question 93351: I have a few more problems. Can you please show me how to solve these problems such as:
7(6-(-8)) = t/-4 +2,
4x+5 = 3x-3,
6y=5 = 4y-13,and
7p-8 = -4p+6.
Thank you.
Answer by praseenakos@yahoo.com(507) (Show Source): You can put this solution on YOUR website!
Questions:
I have a few more problems. Can you please show me how to solve these problems such as:
7(6-(-8)) = t/-4 +2,
4x+5 = 3x-3,
6y=5 = 4y-13,and
7p-8 = -4p+6.
Answer:
2) 4x + 5 = 3x - 3
Subtract 3x from both sides....
==> 4x + 5 - 3x = 3x - 3 - 3x
==> x + 5 = -3
Subtract 5 from both sides...
==> x + 5 - 5 = -3 - 5
==> x = - 8, which is the solution.
To check your answer, substitute the value, x = -8 in the given expression. Then you will get the same value on both sides of the equal sign.
3)Hope your question is like this... 6y + 5 = 4y - 13
6y + 5 = 4y - 13
subtract 4y from both sides..
6y + 5 - 4y = 4y - 13 - 4y
==> 2y + 5 = - 13
Subtract 5 from both sides.
==> 2y + 5 - 5 = - 13 - 5
==> 2y = -18
Divide both sides by 2
==>
==> y = -9 , which is the solution.
To check your answer, substitute the value, y = -9, in the given expression. Then you will get the same value on both sides of the equal sign.
4) 7p - 8 = -4p + 6.
Add 4p on both sides...
7p - 8 + 4p = -4p + 6 + 4p
11p - 8 = 6
Add 8 on both sides...
==> 11p - 8 + 8 = 6 + 8
==> 11p = 14
divide both sides by 11
==>
==> , hence the solution.
To check your answer, substitute the value, x = 11/14 in the given expression. Then you will get the same value on both sides of the equal sign.
1) Hope your question is correct.
7(6-(-8)) = t/-4 +2,
==>
==>
==>
subtract 2 from both sides...
==>
==>
Multiply both sides by -4
==>
==> , which is the solution.
Please check your question once again. I doubt in place of 6 it is t. If so, proceed as I did in rest of the questions.
Hope you found the explanation useful.
Regards.
Praseena.
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