SOLUTION: Rewrite the middle term as the sum of two terms and then factor completely. 10x2 + 19x + 6 my options are; a)(5x-2)(2x-3) b)(10x + 2)(x + 3) c)(5x + 1)(2x + 6) d)

Question 89866This question is from textbook algebra
: Rewrite the middle term as the sum of two terms and then factor completely. 10x2 + 19x + 6
my options are;
a)(5x-2)(2x-3)
b)(10x + 2)(x + 3)
c)(5x + 1)(2x + 6)
d)(5x + 2)(2x + 3)
I am not even coming close can someone please helop.
This question is from textbook algebra

Found 2 solutions by stanbon, funmath:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Rewrite the middle term as the sum of two terms and then factor completely. 10x^2 + 19x + 6
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You want two numbers whose product is a*c=10*6 = 60
and whose sum is b=19
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The numbers are 4 and 15.
So replace the 19x by 4x+15x to get:
10x^2+4x+15x+6
Factor the 1st two terms and the last two terms separately:
2x(5x+2)+3(5x+2)
Factor again to get the answer:
(5x+2)(2x+3)
==================
Cheers,
Stan H.

Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Rewrite the middle term as the sum of two terms and then factor completely. 10x2 + 19x + 6
my options are;
a)(5x-2)(2x-3)
b)(10x + 2)(x + 3)
c)(5x + 1)(2x + 6)
(5x + 2)(2x + 3)
Multiply the coefficient of x^2 and the constant together.
(10)(6)=60
Then replace the coefficient of x with two integers that multiply to give you 60, but add together to give you the coefficient of x, 19.
(4)(15)=60 and 4+15=19

Then factor by grouping:

Happy Calculating!!!
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