SOLUTION: The perimeter of a rectangular field is 60 meters. Its area is 2, square meters. What are its dimensions? Thank you!

Question 893389: The perimeter of a rectangular field is 60 meters. Its area is 2, square meters. What are its dimensions?
Thank you!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangular field is 60 meters. Its area is 2, square meters. What are its dimensions?
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2L + 2W = 60
L*W = 2 --> L = 2/W
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L + W = 30
2/W + W = 30
2 + W^2 = 30W
W^2 - 30W + 2 = 0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=892 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 29.9331845230681, 0.0668154769319216. Here's your graph:

==============
W = 0.0668154769319216 m
L = 29.9331845230681 m
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