SOLUTION: Emma paid the $9.93 bill for her lunch with 226 coins consisting of pennies, nickels and dimes. If the number of nickels plus the number of dimes was equal to the number of pennies
Algebra.Com
Question 888019: Emma paid the $9.93 bill for her lunch with 226 coins consisting of pennies, nickels and dimes. If the number of nickels plus the number of dimes was equal to the number of pennies, then how many coins of each type did she use?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
p+5n+10d=993
p+n+d=226
n+d=p
n=50 d=63 p=113
RELATED QUESTIONS
Emma paid the $10.02 bill for her lunch with 234 coins consisting of pennies, nickels and (answered by ikleyn)
Emma paid the
$
8.12 bill for her lunch with
194 coins consisting of pennies,... (answered by josgarithmetic)
Emma paid the $11.14 bill for her lunch with 248 coins consisting of pennies, nickels,... (answered by Aldorozos)
Emma paid the $10.43 bill for her lunch with 236 coins consisting of pennies, nickels,... (answered by richwmiller)
Emma paid the $10.46 bill for her lunch with 242 coins consisting of pennies,nickels,and... (answered by CubeyThePenguin)
Emma paid the $10.36 bill for her lunch with 232 coins consisting of pennies, nickels,... (answered by TimothyLamb)
Susan paid for her library fine with 12 coins consisting of nickels and dimes. If the... (answered by Alan3354)
Isabelle paid for her $1.75 lunch with 87 coins. If all the coins were nickels and... (answered by greenestamps)
jeremy pays for lunch using 75 coins consisting of quaters and nickels . if the total for (answered by schrammbledeggs)