SOLUTION: The length of a rectangle is 26 inches more than its width. If the area of the rectangle is 855 square inches, what are the length and the width?

Question 87568This question is from textbook Intermediate Algebra
: The length of a rectangle is 26 inches more than its width. If the area of the rectangle is 855 square inches, what are the length and the width? This question is from textbook Intermediate Algebra

Answer by SandySharma(35) (Show Source): You can put this solution on YOUR website!
Let the width of the rectangle be x in.
then length will be x + 26.
Area of rectangle = length X width = x(x + 26)
Given area = 855 square inches
so, x(x + 26) = 855
x^2 + 26x = 855
x^2 + 26x - 855 = 0
now factorize it;
(x+45)(x-19) = 0
now, x = 19 (discard the negative value coz width can't be negative)
length = x + 26 = 19 + 26 =45
Answer: length=45, width = 19

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