SOLUTION: 3. In captivity, the average life span of a grizzly bear is 9 years more than that of a tiger. The sum of the two average life spans is 41 years. Find the average life span of a ti

Algebra.Com
Question 87283: 3. In captivity, the average life span of a grizzly bear is 9 years more than that of a tiger. The sum of the two average life spans is 41 years. Find the average life span of a tiger in captivity.
a. Define the variables.
A = average sum
B = bears life span
T = tiger life span
b. Write the expression for the life span of a grizzly bear in terms of the life span of a tiger.
A = B + T and
T = B - 9
c. Write an equation for the sum of their life spans in term of one variable.
A = B+T
41=
d. Solve the equation for the life span of a tiger.

Answer by rossiv53(27)   (Show Source): You can put this solution on YOUR website!
Tigers life span = T. Since the bear has a life span 9 years longer than the tiger, B = T+9. Both life spans are equal to 41 years.
T+(T+9)=41
2T+9=41
2T+9-9=41-9
2T=32
2T/2=32/2
T=16
So average tiger is 16 and bear is 25 since their average life is 9 years longer.
Good luck!

RELATED QUESTIONS

3. In captivity, the average life span of a grizzly bear is 9 years more than that of a... (answered by stanbon)
the life span of a lynx is about 3/4th the life span of cougar.the average life span of... (answered by josgarithmetic)
The maximum running speed of an elk over approximately quater- mile distance is about... (answered by checkley77)
A random sample of 100 recorded deaths in an urban city during the past year showed an... (answered by stanbon)
A random sample of 100 recorded deaths in an urban city during the past year showed an... (answered by stanbon)
Biologists at the Long Beach aquarium would like to know if conditions at... (answered by stanbon)
9. The life span of a battery is normally distributed, with a mean of 2500 hours and a... (answered by ewatrrr)
The life span of one species of a maple tree is normally distributed with mean 20 years... (answered by stanbon)
Please kindly help me. I am stuck with this question and cannot move on. Thank you again (answered by stanbon)