SOLUTION: I don't know how check to make sure the answer is right. 1500/45=2000/x 1500x=2000*45 1500x=90001500x/1500=90000/1500 x=90000/1500 x=60 I know the answer is correct but I nee

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Question 86519This question is from textbook algebra structure and method
: I don't know how check to make sure the answer is right.
1500/45=2000/x
1500x=2000*45
1500x=90001500x/1500=90000/1500
x=90000/1500
x=60
I know the answer is correct but I need to check it now.
Could you tell me how to do that.
Thank you This question is from textbook algebra structure and method

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
To check this, simply plug the solution back into the original equation

plug in
Reduce the left side
Solved by pluggable solver: Reducing Fractions Calculator
In order to reduce , the numerator and denominator must share a common factor. This common number must evenly divide into both of them without any remainder or decimal.


In order to completely reduce the fraction, you must divide the numerator and the denominator by the greatest common factor (GCF). The GCF of and is AMP Parsing Error of []: Invalid expression '': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . (note: click here if you need help with finding the GCF). So divide both the numerator and denominator by AMP Parsing Error of []: Invalid expression '': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. .



In other words, to reduce the fraction you do this




AMP Parsing Error of [(1500/)/(45/)]: Invalid expression ')/(45/)': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . Plug in the numerator, denominator, and the GCF


AMP Parsing Error of [(100)/(45/)]: Invalid expression ')': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . Now divide 1500 by to get 100. This is now the new numerator.


Now divide 45 by to get 3. This is now the new denominator.



So

AMP Parsing Error of [(1500/)/(45/)=100/3]: Invalid expression ')/(45/)=100/3': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. .




This means that reduces to



In other words,






Reduce the right side
Solved by pluggable solver: Reducing Fractions Calculator
In order to reduce , the numerator and denominator must share a common factor. This common number must evenly divide into both of them without any remainder or decimal.


In order to completely reduce the fraction, you must divide the numerator and the denominator by the greatest common factor (GCF). The GCF of and is AMP Parsing Error of []: Invalid expression '': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . (note: click here if you need help with finding the GCF). So divide both the numerator and denominator by AMP Parsing Error of []: Invalid expression '': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. .



In other words, to reduce the fraction you do this




AMP Parsing Error of [(2000/)/(60/)]: Invalid expression ')/(60/)': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . Plug in the numerator, denominator, and the GCF


AMP Parsing Error of [(100)/(60/)]: Invalid expression ')': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . Now divide 2000 by to get 100. This is now the new numerator.


Now divide 60 by to get 3. This is now the new denominator.



So

AMP Parsing Error of [(2000/)/(60/)=100/3]: Invalid expression ')/(60/)=100/3': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. .




This means that reduces to



In other words,






So now we're left with this



which is true. So the answer is verified
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