SOLUTION: 9a+6b+1c=398 10a+4b+2c=164 12a+4b+1c=58 I have to max a,b,c

Question 847519: 9a+6b+1c=398
10a+4b+2c=164
12a+4b+1c=58
I have to max a,b,c
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
9a+6b+1c=398
10a+4b+2c=164
12a+4b+1c=58
----------------
9a+6b+1c=398
5a+2b+1c=82 2nd eqn x 1/2
12a+4b+1c=58
-------------
All c's have the same coefficient, eliminate c
9a+6b+1c=398
5a+2b+1c=82
----------------- Subtract
4a + 4b = 316 Eqn A
====================
5a+2b+1c=82
12a+4b+1c=58
------------------ Subtract
7a + 2b = -24
2a + 2b = 158 Eqn A x 1/2
--------------------------------- Subtract
5a = -182
a = -182/5
==============
Sub for a, find b
Sub for a and b, find c
===========================
That is the unique solution, there's no max or min.
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