SOLUTION: I am having a difficult time with these problems any help would be appreciated. I think I am trying to make this harder than what it is. That is usually what I do. Could you Pleas

Algebra ->  Algebra  -> Expressions-with-variables -> SOLUTION: I am having a difficult time with these problems any help would be appreciated. I think I am trying to make this harder than what it is. That is usually what I do. Could you Pleas      Log On

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 Algebra: Expressions involving variables, substitution Solvers Lessons Answers archive Quiz In Depth

 Question 8308: I am having a difficult time with these problems any help would be appreciated. I think I am trying to make this harder than what it is. That is usually what I do. Could you Please show how you got the answer. Thank You! here are the instructions: Solve Each Equation x/2 + x/5 + x/3 = 31 Solve each formula for the indicated variable. R(r1 + r2) = r1r2, for R Solve for x. State any restrictions on the variables. b(5px-3c) = a(qx-4) 3ax/5 - 4c= ax/5Answer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!1)Solve: Add the fractions on the left side. Common denominator is 30. Multiply both sides by 30. Divide both sides by 31. 2)Solve for R Divide both sides by (r1+r2) 3) Solve for x. Divide both sides by b. Separate the right side into 2 terms. Add 3c to both sides. Subtract from both sides. Factor the x from the left side. Simplify both sides then divide both sides by = Cancel the b's Restriction: aq may not = 5bp 4) Solve Add 4c to both sides. Subtract ax/5 from both sides. Multiply both sides by 5. Divide both sides by 2a and simplify. Restriction: a cannot = 0