SOLUTION: Solve the system by substitution:
2x+2y=0
y=4x+0
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Question 82571: Solve the system by substitution:
2x+2y=0
y=4x+0
Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
2x+2y=0 [substitute (y=4x+0) for the y-term and solve for the x-term]
.
2x+2(4x+0)=0
2x+2(4x)=0
2x+8x=0
10x=0
10x/10=0/10
x=0
.
solve for the y-term by plugging x=0 back into one of the original equations:
2x+2y=0
2(0)+2y=0
2y=0
2y/2=0/2
y=0
.
check by plugging the values for x and y back into either eiquation and solve:
2x+2y=0
2(0)+2(0)=0
0=0 [checks out].
and
y=4x+0
0=4(0)+0
0=0 [also checks out]
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