SOLUTION: -3(b-8)-5=9(b+2)+1

Algebra.Com
Question 8254: -3(b-8)-5=9(b+2)+1
Answer by bonster(299)   (Show Source): You can put this solution on YOUR website!
-3(b-8)-5=9(b+2)+1
-3b+24-5=9b+18+1
-3b+19=9b+19
19=12b+19
0=12b
b=0

RELATED QUESTIONS

-3(b-8)-5=9(b+2)+1 (answered by bonster)
-3(b-8)-5+9(b+2)=1 (answered by jim_thompson5910)
8-1(3+b)=b+9 (answered by JulietG)
-3=1/2(8)+b (answered by lynnlo)
A=[ 5 0 -9       
   -5 6  2] 
  
B=[ 2  7                  
   -2 -4]... (answered by Edwin McCravy,AnlytcPhil)
let A = [3 -8 -5] [-4 -1 5] [-1 -9 -2] and B = [-4 -7 -1] [8 -1 8] [-3 -3 7] (answered by ikleyn)
1/a-b+ 2/b-a+ 3/a-b+ 4/b-a+ 5/a-b+ 6/b-a+ 7/a-b+ 8/b-a= ?/a-b I think the ? mark would... (answered by scott8148)
ε = {1,2,3,4,5,6,7,8,9,10} A = {2,4,6,8,10} B = {1,3,5,7} C = {1,2,4,5,6,8,9,10}... (answered by MathLover1)