SOLUTION: How do you solve for x y z by elimination method 2x-3y+4z=6 5x+y+3z=14 3x+2y-z=0

Question 825255: How do you solve for x y z by elimination method
2x-3y+4z=6
5x+y+3z=14
3x+2y-z=0
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Choose any variable you want. ..... I had a description here, but decided to delete it...

I would start with the y or the z variable in your example. Choosing z:

Multiply the 3x+2y-z=0 by 4, and add it to the first equation.
Multiply this same equation by 3, and add it to the second equation.
You have now eliminated z, and you should have a system in x and y, without any z.
Now, decide how to multiply which equation so you can add or subtract it from the other equation and eliminate either the x or the y. You could then simply solve for the apparant variable. Now, find the other two variables through back-substitution for the variable you finally found.
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