SOLUTION: Simplify {{{(5x^2/4x) + (1/x) = 1}}} Using LCD I ended up with (5x^2 +4) / 4x where do I go from here?

Question 81206: Simplify
Using LCD I ended up with (5x^2 +4) / 4x where do I go from here?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!

:
You can cancel the x in the denominator of the 1st fraction (does not make much difference here):

:
Multiplying the equation by 4x gets rid of the denominators, so you have:
5x^2 + 4 = 4x
:
5x^2 - 4x + 4 = 0
:
That's about all you can do with it; you can see by the discriminant that it has no real roots. (16 - 4* 5 * 4 = - 64)
RELATED QUESTIONS
{{{(5x/4)+(1/x)}}} I thought LCD and got {{{(5x^2)/(4x) + 4/(4x)}}} but don't know... (answered by Edwin McCravy)

I need to solve this equation: 10/(x^2-2x)+4/x=5/(x-2) so far I have 4x+2/(x^2-2x) =... (answered by mananth)

[(7x^2-9x+4)-(9x^2+3x-2)]-[(5x^2+4x-6)+(-8x^2+6x+1)] Ok I can get all the way to the (answered by funmath,bucky)

Solve 4x^3-36x=0 4x(x^2-9) where do I go from... (answered by Alan3354)

simplify the fractional expression: {{{ sqrt(1+(x^3 - 1/4x^3)^2)}}} This is the... (answered by friesr)

Here is an equation i am trying to simplify: 4x^2-3x^2+5x-x^2-1 (where x is a... (answered by jim_thompson5910)

simplify... (answered by Alan3354)

Multiply the following binomials using the FOIL method: (x � 2)(x + 4) I have... (answered by stanbon)

Can I get your help? My problem is this: {{{3x=1+sqrt(4x^2+x+7)}}} I started by... (answered by Alan3354,stanbon)