SOLUTION: How do you solve the system of equations below for a and b:
32=a*b^2
128=a*b^3
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Question 805721: How do you solve the system of equations below for a and b:
32=a*b^2
128=a*b^3
Found 2 solutions by Alan3354, KMST:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
32=a*b^2
128=a*b^3
------------
128=a*b^3
32=a*b^2
------------ Divide
4 = b
a = 2
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Dividing the second equation by the first,
Then, substituting that value for
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