SOLUTION: The question for solving systems using substitution is: 6x-4y=54 and -9x+2y=-69 I tried to solve it by getting x variable alone in 6x-4y=54 and rewrote it into 6x=-4y+54/6

Algebra.Com
Question 805693: The question for solving systems using substitution is: 6x-4y=54 and -9x+2y=-69
I tried to solve it by getting x variable alone in 6x-4y=54 and rewrote it into 6x=-4y+54/6
I don't know if I am doing it right,thanks.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
The question for solving systems using substitution is: 6x-4y=54 and -9x+2y=-69
I tried to solve it by getting x variable alone in 6x-4y=54 and rewrote it into
-----------
6x=-4y+54/6 **** You divided 54 by 6, but not the other terms.
============
6x-4y=54
-9x+2y=-69
=============
Usually, you solve one eqn for x or y, then sub into the other one. For this one, that would cause fractions, so I'll solve for 2y and sub for that.
3x-2y = 27 --> 2y = 3x - 27
-9x+2y=-69
------
Sub for 2y in the 2nd eqn
-9x+2y=-69
-9x+ (3x-27) = -69
-6x = -42
x = 7
------------
Sub for x in any eqn and find y

RELATED QUESTIONS

I need help solving systems using substitution in the following problem :6x-4y=54... (answered by oscargut)
I am solving Linear systems algebraically of equation's using substitution. The question... (answered by TimothyLamb)
how do i solve 6x – 4y = 54 –9x + 2y = –69 with the substituteion method? (answered by TutorDelphia)
What is the solution for 2y=x+3 and x=y in Solving Systems Using... (answered by rmromero)
Hi there, This is my question: State how many solutions exist for each set of equations... (answered by scott8148)
My question is in reference to one involving "Solving systems of linear equations by the... (answered by Earlsdon)
How to solve linear equations using any method. FOr this one I tried using the... (answered by macston)
I need help on this question it says Solve the systems using substitution. 3x + 2y = -4 (answered by jerryguo41)
I really didn't know where to submit this question but I have been working on it for... (answered by jim_thompson5910)