SOLUTION: Can you help me I have a bunch of these and I am not sure how to solve for them? I am studing for a final and can't remember how to do these. 5d-3=-18 , 3-4c=-13, 2x+1=-4+7x,

Algebra ->  Expressions-with-variables -> SOLUTION: Can you help me I have a bunch of these and I am not sure how to solve for them? I am studing for a final and can't remember how to do these. 5d-3=-18 , 3-4c=-13, 2x+1=-4+7x,       Log On


   

Question 7970: Can you help me I have a bunch of these and I am not sure how to solve for them? I am studing for a final and can't remember how to do these. 5d-3=-18 , 3-4c=-13, 2x+1=-4+7x, -4-5x=2x+10, 2x+2(r+1)=30, 9m-4(m-3)=27
Found 2 solutions by ichudov, bonster:
Answer by ichudov(507) About Me  (Show Source):
You can put this solution on YOUR website!
try using my simplifier (click on the link). I will do one and you do the rest.
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: x=1.
  • Graphical form: Equation 2x%2B1=-4%2B7x was fully solved.
  • Text form: 2x+1=-4+7x simplifies to 0=0
  • Cartoon (animation) form: simplify_cartoon%28+2x%2B1=-4%2B7x+%29
    For tutors: simplify_cartoon( 2x+1=-4+7x )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at 2%2Ax%2B1=-highlight_red%28+4+%29%2B7%2Ax.
Moved -4 to the right of expression
It becomes 2%2Ax%2B1=7%2Ax-highlight_green%28+4+%29.
Look at 2%2Ax%2B1=highlight_red%28+7%2Ax-4+%29.
Moved these terms to the left highlight_green%28+-7%2Ax+%29,highlight_green%28+4+%29
It becomes 2%2Ax%2B1-highlight_green%28+7%2Ax+%29%2Bhighlight_green%28+4+%29=0.
Look at 2%2Ax%2Bhighlight_red%28+1+%29-7%2Ax%2Bhighlight_red%28+4+%29=0.
Added fractions or integers together
It becomes 2%2Ax%2Bhighlight_green%28+5+%29-7%2Ax=0.
Look at 2%2Ax%2Bhighlight_red%28+5+%29-7%2Ax=0.
Moved 5 to the right of expression
It becomes 2%2Ax-7%2Ax%2Bhighlight_green%28+5+%29=0.
Look at highlight_red%28+2%2Ax+%29-highlight_red%28+7%2Ax+%29%2B5=0.
Eliminated similar terms highlight_red%28+2%2Ax+%29,highlight_red%28+-7%2Ax+%29 replacing them with highlight_green%28+%282-7%29%2Ax+%29
It becomes highlight_green%28+%282-7%29%2Ax+%29%2B5=0.
Look at %28highlight_red%28+2+%29-highlight_red%28+7+%29%29%2Ax%2B5=0.
Added fractions or integers together
It becomes %28highlight_green%28+-5+%29%29%2Ax%2B5=0.
Look at %28highlight_red%28+-5+%29%29%2Ax%2B5=0.
Removed extra sign in front of -5
It becomes %28-highlight_green%28+5+%29%29%2Ax%2B5=0.
Look at highlight_red%28+%28-highlight_red%28+5+%29%29%2Ax+%29%2B5=0.
Remove unneeded parentheses around factor highlight_red%28+5+%29
It becomes -highlight_green%28+5+%29%2Ax%2B5=0.
Look at highlight_red%28+-5%2Ax%2B5+%29=0.
Solved linear equation highlight_red%28+-5%2Ax%2B5=0+%29 equivalent to -5*x+5 =0
It becomes highlight_green%28+0+%29=0.
Result: 0=0
This is an equation! Solutions: x=1.

Universal Simplifier and Solver


Done!

Answer by bonster(299) About Me  (Show Source):
You can put this solution on YOUR website!
All you're doing is trying to isolate the variables from the numbers. So here it goes:

5d-3=-18 , <--add 3 to both sides so that you ONLY have 5d on one side
(5d-3)+3=(-18)+3
5d=-15 <--divide both sides by 5
5d%2F5=-15%2F5
d=-3

3-4c=-13, <--subtract 3 from both sides
(3-4c)-3=-13-3
-4c=-16 <--divide both sides by -4
-4c%2F-4=-16%2F-4
c=4

2x%2B1=-4%2B7x, <--subtract 2x from both sides
(2x+1)-2x=(-4+7x-2x)
1=-4%2B5x <--add 4 to both sides
(1)+4=(-4+5x)+4
5=5x <--divide both sides by 5
5%2F5=5x%2F5
1=x

-4-5x=2x+10, <--add 5x to both sides
%28-4-5x%29%2B5x=%282x%2B10%29%2B5x
-4=7x+10 <--subtract 10 from both sides
(-4)-10=(7x+10)-10
-14=7x <--divide both sides by 7
-14%2F7=7x%2F7
-2=x

5r+2(r+1)=30,
5r+2r+2=30
7r+2=30
(7r+2)-2=(30)-2
7r=28
7r%2F7=28%2F7
r=4

9m-4(m-3)=27
9m-4m+12=27
5m+12=27 <--subtract 12 from both sides
(5m+12)-12=(27)-12
5m=15 <--divide both sides by 5
5m%2F5=15%2F5
m=3