SOLUTION: Help with factoring I need to factor and then solve for x
(x+1)(2x+1)^3 -3(2x+1)^2 (x+1)=0
I know that factored it is:
2(x+1)(2x+1)(2x^2+2x-1)
And solved for x it is:
x=-1
Algebra.Com
Question 775977: Help with factoring I need to factor and then solve for x
(x+1)(2x+1)^3 -3(2x+1)^2 (x+1)=0
I know that factored it is:
2(x+1)(2x+1)(2x^2+2x-1)
And solved for x it is:
x=-1, x= -.5, x=(-sqrt(3)-1)/2)(about -1.366), x= (sqrt(3)-1)/2)(about .366)
But no matter how I work it I am unable to end up where I am supposed to be, please mkae steps as clear as possible, thank you.
Found 2 solutions by MathLover1, stanbon:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
..factor out
..use zero product rule to find solutions
if =>
if => =>...this solution doubles
if =>
so, here you have three possible real solutions
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Help with factoring I need to factor and then solve for x
(x+1)(2x+1)^3 -3(2x+1)^2 (x+1)=0
Factored it is:
(x+1)(2x+1)^2[2x+1-3] = 0
2(x+1)(2x+1)^2*(x-1) = 0
And solved for x it is:
x= -1, x= +1 , x = -1/2 with multiplicity two
------
Cheers,
Stan H.
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