SOLUTION: Multiply : (4x^2y^2), (6ax^2y^6) The answer I came up with is: 24ax^4y^12 Explanation for my answer: I multiplied 4*6, then x^2 and left the "a" as is. I also muliplied y^2 * y

Algebra ->  Algebra  -> Expressions-with-variables -> SOLUTION: Multiply : (4x^2y^2), (6ax^2y^6) The answer I came up with is: 24ax^4y^12 Explanation for my answer: I multiplied 4*6, then x^2 and left the "a" as is. I also muliplied y^2 * y      Log On

Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 77529: Multiply : (4x^2y^2), (6ax^2y^6)
The answer I came up with is: 24ax^4y^12
Explanation for my answer: I multiplied 4*6, then x^2 and left the "a" as is. I also muliplied y^2 * y^6. Please help me thank you!
Answer by Earlsdon(6103) About Me  (Show Source):
You can put this solution on YOUR website!
Well, you've got the right idea!
Let's go through the steps:
%284x%5E2y%5E2%29%286ax%5E2y%5E6%29
1) Multiply the integers: 4%2A6+=+24 You did this correctly.
2) Leave the a alone. You did this ok.
3) Multiply the x's. x%5E2+%2A+x%5E2+=+x%5E4 Add the exponents! You did this ok.
4) Multiply the y's. y%5E2+%2A+y%5E6+=+y%5E8 Here you must have multiplied the exponents to gety%5E12 rather than added them to gety%5E8.
So:
%284x%5E2y%5E2%29%286ax%5E2y%5E6%29+=+24ax%5E4y%5E8