SOLUTION: x+ 3y=16 2x-y=4 How do I rearrange these equasions to find x and y?

Question 71737This question is from textbook Saxon Algebra 1
: x+ 3y=16
2x-y=4
How do I rearrange these equasions to find x and y? This question is from textbook Saxon Algebra 1

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x+ 3y=16
2x-y=4
-----------
There are several ways to solve the system:
substitution is usually the 1st way taught
Solve the 1st for x::
x=16-3y
Substitute that into the 2nd equation:
2(16-3y)-y = 4
Now you have no"x" terms so solve for "Y";
32-6y-y=4
32-7y=4
-7y=-28
y=4
Now, solve for x where x=16-3y
x=16-3(4)
x=4
ANSWER:: x=4,y=4
Cheers,
Stan

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