SOLUTION: The product of two consecutive positive even integers is 360. Find the integers. Let the x=first even integer. Then x+2 is the next even integer. Their product is 360: x(x+2

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Question 71187: The product of two consecutive positive even integers is 360. Find the integers.
Let the x=first even integer. Then x+2 is the next even integer.
Their product is 360: x(x+2)=360.
You have a quadratic: x^2+2x-360=0
Factor: (x-18)(x+20)=0
x=18, x+2=20
18*20=360
The integers are 18 and 20.

Found 2 solutions by elima, galactus:
Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
The product of two consecutive positive even integers is 360. Find the integers.
let x = integer.
since they are positive even integers, the next integer will be;
x+2 = integer #2
equation;
x(x+2)=360
x%5E2+2x=360
subtract both sides by 360;
x%5E2+2x-360=0
factor;
(x-18)(x+20)=0
x-18=0 x+20=0
x=18 x=-20
since they are even integers, they answer has to be;
x=18
now plug 18 into the equation for x;
18(18+2)=360
18(20)=360
360=360
so your integers are; 18 and 20
:)

Answer by galactus(183) About Me  (Show Source):