SOLUTION: Please help me divide these and put the answers in simplest form: 1.) {{{(9x^2y)/(5)}}} � {{{(3xy^2)/(20)}}} 2.) {{{(21)/(a+6)}}} � {{{(14)/(a^2-36)}}} 3.) {{{(n^4-4n^3+n-

Question 696858: Please help me divide these and put the answers in simplest form:
1.) �
2.) �
3.)
4.)

Answer by mathbird(71) (Show Source): You can put this solution on YOUR website!
1)9x^2y/5�3xy^2/20
9x^2y/5* 20/3xy^2
12x/y
2)21/a+6 � 14/a^2-36
a^2-36=(a+6)(a-6)
21/a+6 * (a-6)(a+6)/14
3(a-6)/2
3)
{n^3(n-4)+1(n-4)}/(n-4)
{(n^3+1)(n-4)}/(n-4)
n^3+1
4)

2a^2+7a+5
3a-1√(6a^3+19a^2+8a-5)
�6a^3 ∓2a^2
___________________
21a^2+8a
�21a^2∓7a
_________________________
15a-5
�15a∓5
____________________________
0
hence ans is 2a^2+7a+5

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