SOLUTION: I need help with these problems. My book says to multiply and put in simplest form. 1.) (b+4)/(2)^2 times (3)/(b+4)^3 2.) (b+4)/(b-2) times (b^2)-(4)/(b^2)-(16)

Question 696849: I need help with these problems. My book says to multiply and put in simplest form.
1.) (b+4)/(2)^2 times (3)/(b+4)^3
2.) (b+4)/(b-2) times (b^2)-(4)/(b^2)-(16)

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
multiply and put in simplest form.
1.) (b+4)/(2)^2 times (3)/(b+4)^3
----
[(b+4)/4] * [3/[(b+4)(b^2-4b+16)]]
----
Cancel any factor(s) common to a numerator and a denominator:
[1/4] * [3/[(b^2-4b+16)]]
------
= 3/[4(b^2-4b+16)]
========================

2.) (b+4)/(b-2) times (b^2)-(4)/(b^2)-(16)
----
[(b+4)/(b-2)] * [[(b-2)(b+2)/(b-4)(b+4)]
----
Cancel where you can:
----
[1/1] * [[(b+2)/(b-4)]
==============
= (b+2)/(b-4)
=================
Cheers,
Stan H.
=================

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