SOLUTION: solving for the substitution 3x-3y=6 -3x+y=2

Question 678508: solving for the substitution 3x-3y=6 -3x+y=2
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
3x - 3y = 6
-3x + y = 2
...
Rearrange the second equation as y = 3x + 2
Substitute that into the first equation for y
3x - 3(3x+2) = 6
Distribute the -3
3x - 9x - 6 = 6
Combine like terms
-6x = 6 + 6
-6x = 12
Divide both sides by -6
x = -2
...
Substitute x into rearranged equation to solve for y
y = 3(-2) + 2 = -6 + 2 = -4
...
x = -2
y = -4
...
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