SOLUTION: factor completely 4(x+3)(x+3)-25 okay, i am doing "q-factoring" and all i know is subsitution for the function in parentheses is nesssicary. please help.

SOLUTION: factor completely 4(x+3)(x+3)-25 okay, i am doing "q-factoring" and all i know is subsitution for the function in parentheses is nesssicary. please help.

Algebra.Com

Question 676263: factor completely
4(x+3)(x+3)-25
okay, i am doing "q-factoring" and all i know is subsitution for the function in parentheses is nesssicary. please help.

Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Substitute

for

Now it should be clear that you have the difference between two squares. Factor to a pair conjugate binomials and then replace

with the original

. Finally, simplify both factors.

John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it

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