SOLUTION: Mr.James wanted to plant a garden that would be in the shape of a rectangle . He was given 80ft. of fencing to enclose his garden. He wants the length to be 10ft. more than twice t

Algebra ->  Expressions-with-variables -> SOLUTION: Mr.James wanted to plant a garden that would be in the shape of a rectangle . He was given 80ft. of fencing to enclose his garden. He wants the length to be 10ft. more than twice t      Log On


   

Question 67168: Mr.James wanted to plant a garden that would be in the shape of a rectangle . He was given 80ft. of fencing to enclose his garden. He wants the length to be 10ft. more than twice the width. What are the dimensions, in feet, for a rectangular garden that will use exactly 80ft. of fencing?
Answer by Zoop(21) About Me  (Show Source):
You can put this solution on YOUR website!
Okay. This is another perimeter problem.
To solve this, let's express length and width as variable equations:
Length=2x+10
Width=x
That means two times the length plus two times the width should be the perimeter, which in this case is 80.
In equation format, this would mean:
2%282x%2B10%29%2B2x=80
Simplified: (factor it out)
4x%2B20%2B2x=80
Simplified: (combine like terms)
6x%2B20=80
Simplified: (isolate variables)
6x=60
Simplified: (simplify)
x=10
That means:
width=10 and length=width%2A2%2B10, which simplifies to length=30.
I hope that helps. :)