SOLUTION: what is the minimum point of the graph of the equation y=2x^2+8x+9

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Question 670293: what is the minimum point of the graph of the equation y=2x^2+8x+9
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

in general, the graph of a quadratic equation y=ax%5E2%2Bbx%2Bc is a parabola.
if a>0, then the parabola has a minimum point and it opens upwards (U-shaped)
the vertex: the x-coordinate of the minimum point (or maximum point) is given by
x=-b%2F2a
then we substitute this x-value into our quadratic function (the y expression), solve it and we will have the (x,+y) coordinates of the minimum (or maximum) point which is called the vertex of the parabola
so, the minimum point of the graph of the equation y=2x%5E2%2B8x%2B9 will be:

the x-coordinate of the minimum point: x=-b%2F2a

x=-8%2F2%2A2
x=-8%2F4
highlight%28x=-2%29
the y-coordinate of the minimum point:
y=2%28-2%29%5E2%2B8%28-2%29%2B9
y=2%2A4-16%2B9
y=8-16%2B9
highlight%28y=1%29